`color{blue} ✍️`Figure 9.18(a) shows the geometry of image formation by a double convex lens. The image formation can be seen in terms of two steps: (i) The first refracting surface forms the image `I_1` of the object O [Fig. 9.18(b)]. The image `I_1` acts as a virtual object for the second surface that forms the image at I [Fig. 9.18(c)]. Applying Eq. (9.15) to the first interface ABC, we get
`color {blue}{(n_1)/(OB) +(n_2)/(BI_1) = (n_2-n_1)/(BC_1)}`
................(9.17)
`color{blue} ✍️` A similar procedure applied to the second interface* `ADC` gives,
`color {blue}{-(n_2)/(DI_1) + (n_1)/(DI) = (n_2-n_1)/(DC_2)}`
..............(9.18)
`color{blue} ✍️` Note that now the refractive index of the medium on the right side of ADC is `n_1`
while on its left it is `n_2`. Further `(DI_1)` is negative as the distance is measuredagainst the direction of incident light.
`color{blue} ✍️` For a thin lens, `BI_1 = DI_1.` Adding Eqs. (9.17) and (9.18), we get
`color {blue}{(n_1)/(OB) + (n_1)/(DI) = (n_2-n_1) (1/((BC)_1) +1/((DC)_2) )}`
.........(9.19)
`color{blue} ✍️` Suppose the object is at infinity, i.e.,
`OB → ∞` and `DI = f`, Eq. (9.19) gives
`color {blue}{(n_1= (n_2-n_1) (1/(BC)_1) +1/(DC)_2)}`
...............(9.20)
`color{blue} ✍️` The point where image of an object placed at infinity is formed is called the focus `F`, of the lens and the distance `f` gives its focal length. A lens has two foci, `F` and `F′`, on either side of it (Fig. 9.19). By the sign convention,
`color{brown} {BC_1= R_1}`
`color{brown} {DC_2 = - R_2}`
`color{blue} ✍️` So Eq. (9.20) can be written as
`color {blue}{1/f = (n_21 - 1) (1/R_1- 1/R_2) \ \ \ \ ( n_(21) = (n_2)/(n_1) )}`
............(9.21)
`color{blue} ✍️` Equation (9.21) is known as the lens maker’s formula.
`color{blue} ✍️` It is useful to design lenses of desired focal length using surfaces of suitable radii of curvature. Note that the formula is true for a concave lens also. In that case `R_1` is negative, `R_2` positive and therefore, f is negative. From Eqs. (9.19) and (9.20),
`color{blue} ✍️` we get
`color {blue}{(n_1)/(OB) + (n_1)/(DI) = (n_1)/f}`
...........(9.22)
`color{blue} ✍️` Again, in the thin lens approximation, `B` and `D` are both close to thenoptical centre of the lens. Applying the sign convention,
`color{brown}{BO = – u, DI = +v},` we get
`color {blue}{1/v - 1/u = 1/f}`
...............(9.23)
`color{blue} ✍️` Equation (9.23) is the familiar thin lens formula. Though we derived it for a real image formed by a convex lens, the formula is valid for both convex as well as concave lenses and for both real and virtual images.
`color{blue} ✍️` It is worth mentioning that the two foci, F and F′, of a double convex or concave lens are equidistant from the optical centre. The focus on the side of the (original) source of light is called the first focal point, whereas the other is called the second focal point.
`color{blue} ✍️` To find the image of an object by a lens, we can, in principle, take any two rays emanating from a point on an object; trace their paths using the laws of refraction and find the point where the refracted rays meet (or appear to meet). In practice, however, it is convenient to choose any two of the following rays:
`color {blue}{(i)}` A ray emanating from the object parallel to the principal axis of the lens after refraction passes through the second principal focus F′ (in a convex lens) or appears to diverge (in a concave lens) from the first principal focus `F`.
`color {blue}{(ii)}` A ray of light, passing through the optical centre of the lens, emerges without any deviation after refraction.
`color {blue}{(iii)}` A ray of light passing through the first principal focus (for a convex lens) or appearing to meet at it (for a concave lens) emerges parallel to the principal axis after refraction. Figures 9.19(a) and (b) illustrate these rules for a convex and a concave lens, respectively.
`color{blue} ✍️` You should practice drawing similar ray diagrams for different positions of the object with respect to the lens and also verify that the lens formula, Eq. (9.23), holds good for all cases.
`color{blue} ✍️` Here again it must be remembered that each point on an object gives out infinite number of rays. All these rays will pass through the same image point after refraction at the lens.
`color {blue}{m = (h')/h = v/u}`
..........(9.24)
`color{blue} ✍️` When we apply the sign convention, we see that, for erect (and virtual) image formed by a convex or concave lens, m is positive, while for an inverted (and real) image, m is negative.
`color{blue} ✍️`Figure 9.18(a) shows the geometry of image formation by a double convex lens. The image formation can be seen in terms of two steps: (i) The first refracting surface forms the image `I_1` of the object O [Fig. 9.18(b)]. The image `I_1` acts as a virtual object for the second surface that forms the image at I [Fig. 9.18(c)]. Applying Eq. (9.15) to the first interface ABC, we get
`color {blue}{(n_1)/(OB) +(n_2)/(BI_1) = (n_2-n_1)/(BC_1)}`
................(9.17)
`color{blue} ✍️` A similar procedure applied to the second interface* `ADC` gives,
`color {blue}{-(n_2)/(DI_1) + (n_1)/(DI) = (n_2-n_1)/(DC_2)}`
..............(9.18)
`color{blue} ✍️` Note that now the refractive index of the medium on the right side of ADC is `n_1`
while on its left it is `n_2`. Further `(DI_1)` is negative as the distance is measuredagainst the direction of incident light.
`color{blue} ✍️` For a thin lens, `BI_1 = DI_1.` Adding Eqs. (9.17) and (9.18), we get
`color {blue}{(n_1)/(OB) + (n_1)/(DI) = (n_2-n_1) (1/((BC)_1) +1/((DC)_2) )}`
.........(9.19)
`color{blue} ✍️` Suppose the object is at infinity, i.e.,
`OB → ∞` and `DI = f`, Eq. (9.19) gives
`color {blue}{(n_1= (n_2-n_1) (1/(BC)_1) +1/(DC)_2)}`
...............(9.20)
`color{blue} ✍️` The point where image of an object placed at infinity is formed is called the focus `F`, of the lens and the distance `f` gives its focal length. A lens has two foci, `F` and `F′`, on either side of it (Fig. 9.19). By the sign convention,
`color{brown} {BC_1= R_1}`
`color{brown} {DC_2 = - R_2}`
`color{blue} ✍️` So Eq. (9.20) can be written as
`color {blue}{1/f = (n_21 - 1) (1/R_1- 1/R_2) \ \ \ \ ( n_(21) = (n_2)/(n_1) )}`
............(9.21)
`color{blue} ✍️` Equation (9.21) is known as the lens maker’s formula.
`color{blue} ✍️` It is useful to design lenses of desired focal length using surfaces of suitable radii of curvature. Note that the formula is true for a concave lens also. In that case `R_1` is negative, `R_2` positive and therefore, f is negative. From Eqs. (9.19) and (9.20),
`color{blue} ✍️` we get
`color {blue}{(n_1)/(OB) + (n_1)/(DI) = (n_1)/f}`
...........(9.22)
`color{blue} ✍️` Again, in the thin lens approximation, `B` and `D` are both close to thenoptical centre of the lens. Applying the sign convention,
`color{brown}{BO = – u, DI = +v},` we get
`color {blue}{1/v - 1/u = 1/f}`
...............(9.23)
`color{blue} ✍️` Equation (9.23) is the familiar thin lens formula. Though we derived it for a real image formed by a convex lens, the formula is valid for both convex as well as concave lenses and for both real and virtual images.
`color{blue} ✍️` It is worth mentioning that the two foci, F and F′, of a double convex or concave lens are equidistant from the optical centre. The focus on the side of the (original) source of light is called the first focal point, whereas the other is called the second focal point.
`color{blue} ✍️` To find the image of an object by a lens, we can, in principle, take any two rays emanating from a point on an object; trace their paths using the laws of refraction and find the point where the refracted rays meet (or appear to meet). In practice, however, it is convenient to choose any two of the following rays:
`color {blue}{(i)}` A ray emanating from the object parallel to the principal axis of the lens after refraction passes through the second principal focus F′ (in a convex lens) or appears to diverge (in a concave lens) from the first principal focus `F`.
`color {blue}{(ii)}` A ray of light, passing through the optical centre of the lens, emerges without any deviation after refraction.
`color {blue}{(iii)}` A ray of light passing through the first principal focus (for a convex lens) or appearing to meet at it (for a concave lens) emerges parallel to the principal axis after refraction. Figures 9.19(a) and (b) illustrate these rules for a convex and a concave lens, respectively.
`color{blue} ✍️` You should practice drawing similar ray diagrams for different positions of the object with respect to the lens and also verify that the lens formula, Eq. (9.23), holds good for all cases.
`color{blue} ✍️` Here again it must be remembered that each point on an object gives out infinite number of rays. All these rays will pass through the same image point after refraction at the lens.
`color {blue}{m = (h')/h = v/u}`
..........(9.24)
`color{blue} ✍️` When we apply the sign convention, we see that, for erect (and virtual) image formed by a convex or concave lens, m is positive, while for an inverted (and real) image, m is negative.